diff --git a/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/README.md b/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/README.md
index a85c563e0..fafaa8251 100755
--- a/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/README.md
+++ b/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/README.md
@@ -1,28 +1,48 @@
 # [1807.Evaluate the Bracket Pairs of a String][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+You are given a string `s` that contains some bracket pairs, with each pair containing a **non-empty** key.
+
+- For example, in the string `"(name)is(age)yearsold"`, there are **two** bracket pairs that contain the keys `"name"` and `"age"`.
+
+You know the values of a wide range of keys. This is represented by a 2D string array `knowledge` where each `knowledge[i] = [keyi, valuei]` indicates that key `keyi` has a value of `valuei`.
+
+You are tasked to evaluate **all** of the bracket pairs. When you evaluate a bracket pair that contains some key `key1`, you will:
+
+- Replace `keyi` and the bracket pair with the key's corresponding `valuei`.
+- If you do not know the value of the key, you will replace `keyi` and the bracket pair with a question mark `"?"` (without the quotation marks).
+
+Each key will appear at most once in your `knowledge`. There will not be any nested brackets in `s`.
+
+Return the resulting string after evaluating **all** of the bracket pairs.
 
 **Example 1:**
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
+Input: s = "(name)is(age)yearsold", knowledge = [["name","bob"],["age","two"]]
+Output: "bobistwoyearsold"
+Explanation:
+The key "name" has a value of "bob", so replace "(name)" with "bob".
+The key "age" has a value of "two", so replace "(age)" with "two".
 ```
 
-## 题意
-> ...
-
-## 题解
+**Example 2:**
 
-### 思路1
-> ...
-Evaluate the Bracket Pairs of a String
-```go
+```
+Input: s = "hi(name)", knowledge = [["a","b"]]
+Output: "hi?"
+Explanation: As you do not know the value of the key "name", replace "(name)" with "?".
 ```
 
+**Example 3:**
+
+```
+Input: s = "(a)(a)(a)aaa", knowledge = [["a","yes"]]
+Output: "yesyesyesaaa"
+Explanation: The same key can appear multiple times.
+The key "a" has a value of "yes", so replace all occurrences of "(a)" with "yes".
+Notice that the "a"s not in a bracket pair are not evaluated.
+```
 
 ## 结语
 
diff --git a/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution.go b/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution.go
index d115ccf5e..7267d8fcf 100644
--- a/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution.go
+++ b/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution.go
@@ -1,5 +1,34 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+import "strings"
+
+func Solution(s string, knowledge [][]string) string {
+	values := make(map[string]string)
+	for _, v := range knowledge {
+		values[v[0]] = v[1]
+	}
+
+	sb := strings.Builder{}
+	var key, replace string
+	left := -1
+	for i, b := range s {
+		if b == '(' {
+			left = i
+			continue
+		}
+		if b == ')' {
+			key = s[left+1 : i]
+			replace = "?"
+			if v, ok := values[key]; ok {
+				replace = v
+			}
+			left = -1
+			sb.WriteString(replace)
+			continue
+		}
+		if left == -1 {
+			sb.WriteByte(byte(b))
+		}
+	}
+	return sb.String()
 }
diff --git a/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution_test.go b/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution_test.go
index 14ff50eb4..a34b43482 100644
--- a/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution_test.go
+++ b/leetcode/1801-1900/1807.Evaluate-the-Bracket-Pairs-of-a-String/Solution_test.go
@@ -9,31 +9,39 @@ import (
 func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
-		name   string
-		inputs bool
-		expect bool
+		name      string
+		inputs    string
+		knowledge [][]string
+
+		expect string
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", "(name)is(age)yearsold", [][]string{
+			{"name", "bob"}, {"age", "two"},
+		}, "bobistwoyearsold"},
+		{"TestCase2", "hi(name)", [][]string{
+			{"a", "b"},
+		}, "hi?"},
+		{"TestCase3", "(a)(a)(a)aaa", [][]string{
+			{"a", "yes"},
+		}, "yesyesyesaaa"},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.inputs, c.knowledge)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.inputs, c.knowledge)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }