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feat: update lc problems (#4812)
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solution/1500-1599/1526.Minimum Number of Increments on Subarrays to Form a Target Array/README.md

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<pre><strong>输入:</strong>target = [3,1,5,4,2]
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<strong>输出:</strong>7
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<strong>解释:</strong>(initial)[0,0,0,0,0] -&gt; [1,1,1,1,1] -&gt; [2,1,1,1,1] -&gt; [3,1,1,1,1]
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<strong>解释:</strong>(initial)[0,0,0,0,0] -&gt; [1,1,1,1,1] -&gt; [2,1,1,1,1] -&gt; [3,1,1,1,1]
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-&gt; [3,1,2,2,2] -&gt; [3,1,3,3,2] -&gt; [3,1,4,4,2] -&gt; [3,1,5,4,2] (target)。
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</pre>
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solution/2100-2199/2130.Maximum Twin Sum of a Linked List/README_EN.md

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<strong>Explanation:</strong>
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Nodes 0 and 1 are the twins of nodes 3 and 2, respectively. All have twin sum = 6.
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There are no other nodes with twins in the linked list.
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Thus, the maximum twin sum of the linked list is 6.
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Thus, the maximum twin sum of the linked list is 6.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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The nodes with twins present in this linked list are:
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- Node 0 is the twin of node 3 having a twin sum of 4 + 3 = 7.
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- Node 1 is the twin of node 2 having a twin sum of 2 + 2 = 4.
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Thus, the maximum twin sum of the linked list is max(7, 4) = 7.
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Thus, the maximum twin sum of the linked list is max(7, 4) = 7.
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</pre>
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<p><strong class="example">Example 3:</strong></p>

solution/2500-2599/2528.Maximize the Minimum Powered City/README_EN.md

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<pre>
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<strong>Input:</strong> stations = [1,2,4,5,0], r = 1, k = 2
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<strong>Output:</strong> 5
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<strong>Explanation:</strong>
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One of the optimal ways is to install both the power stations at city 1.
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<strong>Explanation:</strong>
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One of the optimal ways is to install both the power stations at city 1.
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So stations will become [1,4,4,5,0].
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- City 0 is provided by 1 + 4 = 5 power stations.
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- City 1 is provided by 1 + 4 + 4 = 9 power stations.
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<pre>
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<strong>Input:</strong> stations = [4,4,4,4], r = 0, k = 3
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<strong>Output:</strong> 4
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<strong>Explanation:</strong>
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<strong>Explanation:</strong>
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It can be proved that we cannot make the minimum power of a city greater than 4.
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</pre>
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solution/3600-3699/3632.Subarrays with XOR at Least K/README.md

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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3600-3699/3632.Subarrays%20with%20XOR%20at%20Least%20K/README.md
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tags:
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- 位运算
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-
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- 字典树
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- 数组
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- 前缀和
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---
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<!-- problem:start -->
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# [3632. 子数组异或至少为 K 的数目 🔒](https://leetcode.cn/problems/subarrays-with-xor-at-least-k)
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# [3632. 异或至少为 K 的子数组数目 🔒](https://leetcode.cn/problems/subarrays-with-xor-at-least-k)
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[English Version](/solution/3600-3699/3632.Subarrays%20with%20XOR%20at%20Least%20K/README_EN.md)
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solution/3600-3699/3632.Subarrays with XOR at Least K/README_EN.md

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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3600-3699/3632.Subarrays%20with%20XOR%20at%20Least%20K/README_EN.md
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tags:
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- Bit Manipulation
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- Tree
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- Trie
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- Array
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- Prefix Sum
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---

solution/3600-3699/3657.Find Loyal Customers/README.md

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<li>他们的 <strong>退款率</strong>&nbsp;少于&nbsp;<code>20%</code>。</li>
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</ul>
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<p>退款率是退款交易占交易总数(购买加退款)的比例,计算公式为退款交易数量除以总交易数量。</p>
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<p>返回结果表以&nbsp;<code>customer_id</code> <strong>升序</strong>&nbsp;排序。</p>
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<p>结果格式如下所示。</p>

solution/3600-3699/3657.Find Loyal Customers/README_EN.md

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<li>Their <strong>refund rate</strong> is less than <code>20%</code> .</li>
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</ul>
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<p><em>Refund rate</em> is the proportion of transactions that are refunds, calculated as the number of refund transactions divided by the total number of transactions (purchases plus refunds).</p>
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<p>Return <em>the result table&nbsp;ordered by</em> <code>customer_id</code> <em>in <strong>ascending</strong> order</em>.</p>
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<p>The result format is in the following example.</p>

solution/3600-3699/3666.Minimum Operations to Equalize Binary String/README.md

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source: 第 164 场双周赛 Q4
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tags:
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- 广度优先搜索
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- 哈希表
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- 并查集
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- 数学
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- 有序集合
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---
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<!-- problem:start -->

solution/3600-3699/3666.Minimum Operations to Equalize Binary String/README_EN.md

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source: Biweekly Contest 164 Q4
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tags:
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- Union Find
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- Ordered Set
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<!-- problem:start -->

solution/3700-3799/3701.Compute Alternating Sum/README.md

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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3700-3799/3701.Compute%20Alternating%20Sum/README.md
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rating: 1228
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source: 第 470 场周赛 Q1
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tags:
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- 数组
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- 模拟
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---
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<!-- problem:start -->

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