Integer literal overflow in C causes Rust compilation error #1435
Description
C source code (from LibmCS):
int32_t sign = 0x80000000U;C2Rust 0.21.0 translates it to:
pub type int32_t = __int32_t;
pub type __int32_t = i32;
let mut sign: int32_t = 0x80000000 as int32_t;which causes this compilation error:
error: literal out of range for `i32`
--> src/mathd/sqrtd.rs:42:29
|
42 | let mut sign: int32_t = 0x80000000 as int32_t;
| ^^^^^^^^^^
|
= note: `#[deny(overflowing_literals)]` on by default
= note: the literal `0x80000000` (decimal `2147483648`) does not fit into the type `i32` and will become `-2147483648i32`
= help: consider using the type `u32` instead
C2Rust 0.20.0 translates that to:
pub type int32_t = __int32_t;
pub type __int32_t = libc::c_int;
let mut sign: int32_t = 0x80000000 as libc::c_uint as int32_t;which compiles.
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