[python-dateutil] dateutil.parser.parse() returns a tuple when fuzzy_with_tokens = True

[ellieayla]

dateutil.parser.parse() normally returns a datetime object, as in

typeshed/stubs/python-dateutil/dateutil/parser/_parser.pyi

Lines 95 to 106 in 843c1fd

	def parse(
	timestr: _FileOrStr,
	parserinfo: parserinfo | None = None,
	*,
	dayfirst: bool | None = ...,
	yearfirst: bool | None = ...,
	ignoretz: bool = ...,
	fuzzy: bool = ...,
	fuzzy_with_tokens: bool = ...,
	default: datetime | None = ...,
	tzinfos: _TzInfos | None = ...,
	) -> datetime: ...

However, dateutil.parser.parse(fuzzy_with_tokens=True) returns a tuple instead, like (datetime, tuple[str?])`.

https://github.com/dateutil/dateutil/blob/e081f6725fbb49cae6eedab7010f517e8490859b/src/dateutil/parser/_parser.py#L869-L873

Docs:

https://github.com/dateutil/dateutil/blob/e081f6725fbb49cae6eedab7010f517e8490859b/src/dateutil/parser/_parser.py#L618-L621

https://github.com/dateutil/dateutil/blob/e081f6725fbb49cae6eedab7010f517e8490859b/src/dateutil/parser/_parser.py#L702-L704

[ellieayla]

I think this is just a matter of combining @overload with fuzzy_with_tokens: Literal[False] = ..., ...