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steindevchillenzer
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Update docs/source/models/lasers.rst
Co-authored-by: chillenzer <[email protected]>
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docs/source/models/lasers.rst

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@@ -95,7 +95,7 @@ The result of this last integral can be read off from the known solution for the
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.. math::
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\hat E_x(x, z, \Omega) = &\
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\epsilon_\Omega
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\left[ 1 + \frac{z^2}{z_\mathrm{R,x}^2} \right]^{-1/4}
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\left[ 1 + \frac{z^2}{z_{\mathrm{R},x}^2} \right]^{-1/4}
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e^{-\left[
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x - \left( x_0 - \frac{c}{\Omega_0 w_{0,x}}\alpha z \right)
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\right]^2

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