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| 1 | + |
| 2 | +/* |
| 3 | + * Algorithm: Merge Sort |
| 4 | + * Description: A divide-and-conquer sorting algorithm that recursively splits the array, sorts the halves, and merges them in order. |
| 5 | + * Time Complexity: O(n log n) for best, average, and worst cases |
| 6 | + * Space Complexity: O(n) due to temporary arrays used during merging |
| 7 | + * Author: Ayush Anand |
| 8 | + * Date: 2025-10-01 |
| 9 | + */ |
| 10 | + |
| 11 | +#include <stdio.h> |
| 12 | +#include <stdlib.h> |
| 13 | + |
| 14 | +// Function to merge two sorted subarrays |
| 15 | +void merge(int arr[], int left, int mid, int right) { |
| 16 | + int n1 = mid - left + 1; // Size of left subarray |
| 17 | + int n2 = right - mid; // Size of right subarray |
| 18 | + |
| 19 | + // Dynamically allocate temporary arrays |
| 20 | + int *L = (int *)malloc(n1 * sizeof(int)); |
| 21 | + int *R = (int *)malloc(n2 * sizeof(int)); |
| 22 | + |
| 23 | + if (L == NULL || R == NULL) { |
| 24 | + printf("Memory allocation failed!\n"); |
| 25 | + exit(1); |
| 26 | + } |
| 27 | + |
| 28 | + // Copy data to temporary arrays L[] and R[] |
| 29 | + for (int i = 0; i < n1; i++) |
| 30 | + L[i] = arr[left + i]; |
| 31 | + for (int j = 0; j < n2; j++) |
| 32 | + R[j] = arr[mid + 1 + j]; |
| 33 | + |
| 34 | + // Merge the temporary arrays back into arr[left..right] |
| 35 | + int i = 0, j = 0, k = left; |
| 36 | + |
| 37 | + while (i < n1 && j < n2) { |
| 38 | + if (L[i] <= R[j]) { |
| 39 | + arr[k++] = L[i++]; |
| 40 | + } else { |
| 41 | + arr[k++] = R[j++]; |
| 42 | + } |
| 43 | + } |
| 44 | + |
| 45 | + // Copy remaining elements, if any |
| 46 | + while (i < n1) |
| 47 | + arr[k++] = L[i++]; |
| 48 | + while (j < n2) |
| 49 | + arr[k++] = R[j++]; |
| 50 | + |
| 51 | + // Free dynamically allocated memory |
| 52 | + free(L); |
| 53 | + free(R); |
| 54 | +} |
| 55 | + |
| 56 | +// Recursive function to implement Merge Sort |
| 57 | +void mergeSort(int arr[], int left, int right) { |
| 58 | + if (left < right) { |
| 59 | + int mid = left + (right - left) / 2; |
| 60 | + |
| 61 | + // Recursively sort first and second halves |
| 62 | + mergeSort(arr, left, mid); |
| 63 | + mergeSort(arr, mid + 1, right); |
| 64 | + |
| 65 | + // Merge the sorted halves |
| 66 | + merge(arr, left, mid, right); |
| 67 | + } |
| 68 | +} |
| 69 | + |
| 70 | +// Function to print an array |
| 71 | +void printArray(int arr[], int size) { |
| 72 | + for (int i = 0; i < size; i++) |
| 73 | + printf("%d ", arr[i]); |
| 74 | + printf("\n"); |
| 75 | +} |
| 76 | + |
| 77 | +// Driver code |
| 78 | +int main() { |
| 79 | + int n; |
| 80 | + |
| 81 | + printf("Enter the number of elements: "); |
| 82 | + scanf("%d", &n); |
| 83 | + |
| 84 | + int *arr = (int *)malloc(n * sizeof(int)); |
| 85 | + if (arr == NULL) { |
| 86 | + printf("Memory allocation failed!\n"); |
| 87 | + return 1; |
| 88 | + } |
| 89 | + |
| 90 | + printf("Enter %d elements:\n", n); |
| 91 | + for (int i = 0; i < n; i++) |
| 92 | + scanf("%d", &arr[i]); |
| 93 | + |
| 94 | + printf("Original array: "); |
| 95 | + printArray(arr, n); |
| 96 | + |
| 97 | + mergeSort(arr, 0, n - 1); |
| 98 | + |
| 99 | + printf("Sorted array: "); |
| 100 | + printArray(arr, n); |
| 101 | + |
| 102 | + free(arr); // Free dynamically allocated memory |
| 103 | + return 0; |
| 104 | +} |
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