Deadline can't work well

[chenjie199234]

grpc-go: 1.79.2

package main

import (
	"context"
	"demo/msg"
	"fmt"
	"net"
	"time"

	"google.golang.org/grpc"
	"google.golang.org/grpc/status"
)

func main() {
	c, e := grpc.NewClient("127.0.0.1:8000", grpc.WithInsecure())
	if e != nil {
		panic(e)
	}
	go func() {
		time.Sleep(time.Second * 5)
		cc := msg.NewMsgClient(c)
		ctx, cancel := context.WithDeadline(context.Background(), time.Now().Add(time.Second*5))
		defer cancel()
		_, e := cc.Hello(ctx, &msg.HelloReq{})
		if e != nil {
			fmt.Println("client error:", e)
		}
		time.Sleep(time.Second)
	}()

	//server
	s := grpc.NewServer()
	msg.RegisterMsgServer(s, &Server{})
	l, e := net.Listen("tcp", "127.0.0.1:8000")
	if e != nil {
		panic(e)
	}
	s.Serve(l)
}

type Server struct {
}

func (s *Server) Hello(ctx context.Context, req *msg.HelloReq) (*msg.HelloResp, error) {
	fmt.Println("server get Hello call")
	<-ctx.Done()
	println("server error:", ctx.Err().Error())
	return nil, status.New(400, "code=10000,msg=this is a test").Err()
}

here is the std output:

go run .\main.go
server get Hello call
server error: context canceled
client error: rpc error: code = DeadlineExceeded desc = stream terminated by RST_STREAM with error code: CANCEL

the server should get to deadline before the cancel,because of the time.sleep(time.second) in client's goroutine