openposix: sem_timedwait: replace sleep with tst_process_state_wait3

This makes the test faster and also avoids a small race - when the
time is very close to starting new second, this makes the test use
timeout that's effectively just slightly over one second, because
nanosecond portion is always set to 0. And previously child would
sleep roughly one second.

Signed-off-by: Jan Stancek <jstancek@redhat.com>
Reviewed-by: Petr Vorel <pvorel@suse.cz>
Reviewed-by: Cyril Hrubis <chrubis@suse.cz>

Author: jstancek

testcases/open_posix_testsuite/conformance/interfaces/sem_timedwait/2-1.c

@@ -22,6 +22,7 @@
 #include <time.h>
 #include <sys/mman.h>
 #include "posixtest.h"
+#include "proc.h"
 
 #define TEST "2-1"
 #define SHM_NAME "/posixtest_2-1"
@@ -79,7 +80,8 @@ int main(void)
 	} else if (pid > 0)	// parent to unlock semaphore
 	{
 		int i;
-		sleep(1);
+
+		tst_process_state_wait3(pid, 'S', 1);
 		if (sem_post(mysemp) == -1) {
 			perror(ERROR_PREFIX "sem_post");
 			return PTS_FAIL;

testcases/open_posix_testsuite/conformance/interfaces/sem_timedwait/9-1.c

@@ -21,6 +21,7 @@
 #include <sys/wait.h>
 #include <time.h>
 #include "posixtest.h"
+#include "proc.h"
 
 #define TEST "9-1"
 #define FUNCTION "sem_timedwait"
@@ -79,7 +80,8 @@ int main(void)
 
 	} else {		// parent to send a signal to child
 		int i;
-		sleep(1);
+
+		tst_process_state_wait3(pid, 'S', 1);
 		(void)kill(pid, SIGABRT);	// send signal to child
 		if (wait(&i) == -1) {
 			perror("Error waiting for child to exit\n");