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prep for scheme json version
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‎xml/chapter2/section3/subsection4.xml‎

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@@ -235,12 +235,7 @@ BACADAEAFABBAAAGAH</TD></TR></TABLE>
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there is only one node left, which is the root of the entire tree.
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Here is how the Huffman tree of figure<SPACE/><REF NAME="fig:huffman"/> was
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generated:
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<SPLIT>
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<SCHEME>
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<FIGURE src="img_tex/ch2_3_4-3.png"></FIGURE>
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</SCHEME>
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<JAVASCRIPT>
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<TABLE>
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<TABLE>
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<TR SINGLESPACE="yes">
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<TD>
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Initial leaves
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<LATEXINLINE>$\{$</LATEXINLINE>(<LATEXINLINE>$\{$</LATEXINLINE>A B C D E F G H<LATEXINLINE>$\}$</LATEXINLINE> 17)<LATEXINLINE>$\}$</LATEXINLINE>
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</TD>
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</TR>
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</TABLE>
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</JAVASCRIPT>
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</SPLIT>
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</TABLE>
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The algorithm does not always specify a unique tree, because there may
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not be unique smallest-weight nodes at each step. Also, the choice of
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the order in which the two nodes are merged (i.e., which will be the
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<INDEX>rock songs, 1950s</INDEX>
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rock songs. (Note that the <QUOTE>symbols</QUOTE> of an
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<QUOTE>alphabet</QUOTE> need not be individual letters.)
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<SPLIT>
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<SCHEME>
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<FIGURE src="img_tex/ch2_3_4-4.png"></FIGURE>
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</SCHEME>
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<JAVASCRIPT>
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<TABLE>
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<TABLE>
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<TR SINGLESPACE="yes">
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<TD>
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A
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<SPACE/><SPACE/>1
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</TD>
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</TR>
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</TABLE>
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</JAVASCRIPT>
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</SPLIT>
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</TABLE>
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Use
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<SPLITINLINE>
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<SCHEME><SCHEMEINLINE>generate-huffman-tree</SCHEMEINLINE></SCHEME>

‎xml/chapter3/section1/subsection3.xml‎

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@@ -1045,6 +1045,7 @@ paul_acc("withdraw", "rosebud")(50); // Withdraws 50, should return 40
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</EXERCISE>
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<EXERCISE>
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<LABEL NAME="ex:3_8"/>
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When we defined the evaluation model in
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section<SPACE/><REF NAME="sec:evaluating-combinations"/>, we said that the
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<INDEX>order of evaluation<SUBINDEX><ORDER>JavaScript</ORDER>in JavaScript</SUBINDEX></INDEX>

‎xml/chapter3/section2/section2.xml‎

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<!-- Subsection 4 : Internal Definitions -->
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&amp;subsection3.2.4;
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<!-- Subsection 5 : CSE Machine -->
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&amp;subsection3.2.5;
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</SECTION>

‎xml/chapter3/section2/subsection5.xml‎

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<SUBSECTION>
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<NAME>
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CSE Machine
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</NAME>
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<LABEL NAME="sec:cse-machine"/>
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<INDEX>CSE machine<OPEN/></INDEX>
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<SPLIT>
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<JAVASCRIPT>
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<TEXT>
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The environment model as presented so far focuses on how functions can refer
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to their parameters, locally declared names, and names that are declared
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outside the function. We achieve this by evaluating statements and expressions
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with respect to a <EM>current environment</EM>. It does not specify how
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we keep track of environments as computation proceeds. For example, when we
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evaluate an expression <JAVASCRIPTINLINE>f(x) + y</JAVASCRIPTINLINE>, we
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need to evaluate <JAVASCRIPTINLINE>x</JAVASCRIPTINLINE> in the current
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environment, establish as the new current environment the environment of
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<JAVASCRIPTINLINE>f</JAVASCRIPTINLINE> extended by a binding of its
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parameter to the value of <JAVASCRIPTINLINE>x</JAVASCRIPTINLINE>, and
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evaluate the body of <JAVASCRIPTINLINE>f</JAVASCRIPTINLINE> in this
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extended environment. But what environment should we use for evaluating
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<JAVASCRIPTINLINE>y</JAVASCRIPTINLINE> after
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<JAVASCRIPTINLINE>f</JAVASCRIPTINLINE> returns?
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In this section, we extend the
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</TEXT>
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<SUBHEADING><NAME>Evaluating arithmetic expressions</NAME></SUBHEADING>
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<TEXT>
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Exercise<SPACE/><REF NAME="ex:3_8"/> shows that the presence of
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assignments makes the result of a program depend on the order in which
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the operands of an operator combination are evaluated. To remove
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ambiguities that arise from this, the JavaScript standard specifies
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left-to-right evaluation of operands.
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As an example, consider the evaluation of the arithmetic expression statement
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<SNIPPET>
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<JAVASCRIPT>
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1 + (2 * 3);
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</JAVASCRIPT>
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</SNIPPET>
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The expression is decomposed into its operands
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<JAVASCRIPTINLINE>1</JAVASCRIPTINLINE> and
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<JAVASCRIPTINLINE>2 * 3</JAVASCRIPTINLINE>, followed by the
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<EM>instruction</EM> to add their results.
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</TEXT>
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<INDEX>CSE machine<CLOSE/></INDEX>
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</JAVASCRIPT>
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</SPLIT>
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</SUBSECTION>

‎xml/chapter3/section5/subsection2.xml‎

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by adding <SCHEMEINLINE>fibs</SCHEMEINLINE> to itself shifted by one place:
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<SPLIT>
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<SCHEME>
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<FIGURE src="img_tex/ch3_5_2-1.png"></FIGURE>
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<LATEX>
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\[
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\begin{array}{ccccccccccccl}
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&amp; &amp; 1 &amp; 1 &amp; 2 &amp; 3 &amp; 5 &amp; 8 &amp; 13 &amp; 21 &amp; \ldots &amp; = &amp; \texttt{(stream-cdr fibs)} \\
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&amp; &amp; 0 &amp; 1 &amp; 1 &amp; 2 &amp; 3 &amp; 5 &amp; 8 &amp; 13 &amp; \ldots &amp; = &amp; \texttt{fibs} \\ \hline
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0 &amp; 1 &amp; 1 &amp; 2 &amp; 3 &amp; 5 &amp; 8 &amp; 13 &amp; 21 &amp; 34 &amp; \ldots &amp; = &amp; \texttt{fibs}
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\end{array}
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\]
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</LATEX>
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</SCHEME>
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<JAVASCRIPT>
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<LATEX>

‎xml/chapter5/section5/subsection1.xml‎

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@@ -514,7 +514,16 @@ go_to(reg("continue"))
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<!-- %Whew! What a pain it was to set this, because of the blank lines. -->
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<SPLIT>
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<SCHEME>
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<FIGURE src="img_original/preserving_table.svg"></FIGURE>
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\[
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\begin{array}{l|l|l|l}
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\textit{seq}_1 &amp; \texttt{(save}\ \textit{reg}_1\texttt{)} &amp; \texttt{(save}\ \textit{reg}_2\texttt{)} &amp; \texttt{(save}\ \textit{reg}_2\texttt{)} \\
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\textit{seq}_2 &amp; \textit{seq}_1 &amp; \textit{seq}_1 &amp; \texttt{(save}\ \textit{reg}_1\texttt{)} \\
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&amp; \texttt{(restore}\ \textit{reg}_1\texttt{)} &amp; \texttt{(restore}\ \textit{reg}_2\texttt{)} &amp; \textit{seq}_1 \\
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&amp; \textit{seq}_2 &amp; \textit{seq}_2 &amp; \texttt{(restore}\ \textit{reg}_1\texttt{)} \\
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&amp; &amp; &amp; \texttt{(restore}\ \textit{reg}_2\texttt{)} \\
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&amp; &amp; &amp; \textit{seq}_2
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\end{array}
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\]
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</SCHEME>
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<JAVASCRIPT>
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<LATEX>
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&amp; \texttt{restore(}\textit{reg}_1\texttt{),} &amp; \texttt{restore(}\textit{reg}_2\texttt{),} &amp; \textit{seq}_1 \\
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&amp; \textit{seq}_2 &amp; \textit{seq}_2 &amp; \texttt{restore(}\textit{reg}_1\texttt{),} \\
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&amp; &amp; &amp; \texttt{restore(}\textit{reg}_2\texttt{),} \\
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&amp; &amp; &amp; \textit{seq}_2
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&amp; &amp; &amp; \textit{seq}_2
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\end{array}
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\]
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</LATEX>

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