Add solution and test-cases for problem 2561

leetcode/2501-2600/2561.Rearranging-Fruits/README.md

@@ -0,0 +1,35 @@
+# [2561.Rearranging Fruits][title]
+
+## Description
+
+You have two fruit baskets containing `n` fruits each. You are given two **0-indexed** integer arrays `basket1` and `basket2` representing the cost of fruit in each basket. You want to make both baskets **equal**. To do so, you can use the following operation as many times as you want:
+
+- Chose two indices `i` and `j`, and swap the `ith` fruit of `basket1` with the `jth` fruit of `basket2`.
+- The cost of the swap is `min(basket1[i],basket2[j])`.
+
+Two baskets are considered equal if sorting them according to the fruit cost makes them exactly the same baskets.
+
+Return the minimum cost to make both the baskets equal or `-1` if impossible.
+
+**Example 1:**
+
+```
+Input: basket1 = [4,2,2,2], basket2 = [1,4,1,2]
+Output: 1
+Explanation: Swap index 1 of basket1 with index 0 of basket2, which has cost 1. Now basket1 = [4,1,2,2] and basket2 = [2,4,1,2]. Rearranging both the arrays makes them equal.
+```
+
+**Example 2:**
+
+```
+Input: basket1 = [2,3,4,1], basket2 = [3,2,5,1]
+Output: -1
+Explanation: It can be shown that it is impossible to make both the baskets equal.
+```
+
+## 结语
+
+如果你同我一样热爱数据结构、算法、LeetCode，可以关注我 GitHub 上的 LeetCode 题解：[awesome-golang-algorithm][me]
+
+[title]: https://leetcode.com/problems/rearranging-fruits/
+[me]: https://github.com/kylesliu/awesome-golang-algorithm

leetcode/2501-2600/2561.Rearranging-Fruits/Solution.go

@@ -1,5 +1,51 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+import (
+	"math"
+	"sort"
+)
+
+func Solution(basket1 []int, basket2 []int) int64 {
+	freq := map[int]int{}
+	m := math.MaxInt
+	for _, b := range basket1 {
+		freq[b]++
+		if b < m {
+			m = b
+		}
+	}
+	for _, b := range basket2 {
+		freq[b]--
+		if b < m {
+			m = b
+		}
+	}
+
+	var merge []int
+	for k, c := range freq {
+		if c%2 != 0 {
+			return -1
+		}
+		for i := 0; i < abs(c)/2; i++ {
+			merge = append(merge, k)
+		}
+	}
+
+	sort.Ints(merge)
+	var res int64
+	for i := 0; i < len(merge)/2; i++ {
+		if 2*m < merge[i] {
+			res += int64(2 * m)
+		} else {
+			res += int64(merge[i])
+		}
+	}
+	return res
+}
+
+func abs(a int) int {
+	if a < 0 {
+		return -a
+	}
+	return a
 }

leetcode/2501-2600/2561.Rearranging-Fruits/Solution_test.go

@@ -9,31 +9,30 @@ import (
 func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
-		name   string
-		inputs bool
-		expect bool
+		name             string
+		basket1, basket2 []int
+		expect           int64
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []int{4, 2, 2, 2}, []int{1, 4, 1, 2}, 1},
+		{"TestCase2", []int{2, 3, 4, 1}, []int{1, 2, 5, 1}, -1},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.basket1, c.basket2)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.basket1, c.basket2)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }