Solution #3306 - Mridul/Edited - 11/03/2025 #27
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JRS296
reviewed
Mar 17, 2025
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| Initialization: | ||
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| n: Length of the word. | ||
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| freq: Array to store the frequency of each character. | ||
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| currConsonant: Counter for the current number of consonants in the substring. | ||
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| cnt: Counter for the valid substrings. | ||
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| left: Left pointer for the sliding window. | ||
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| Iterating through the word: | ||
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| For each character ch in the word: | ||
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| If ch is a consonant, increment currConsonant. | ||
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| Increment the frequency of ch in freq. | ||
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| Checking the conditions: | ||
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| While the current substring contains at least k consonants and all vowels: | ||
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| Increment cnt by the number of valid substrings ending at the current position. | ||
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| Move the left pointer to reduce the window size. | ||
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| Decrement the frequency of the character at the left pointer. | ||
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| If the character is a consonant, decrement currConsonant. | ||
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| This logic ensures that we count all substrings that meet the conditions specified in the problem. |
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Can you utilize the markdown like your other PR's? Also add time and space complexity + how this could be further optimized (if possible)
JRS296
requested changes
Mar 17, 2025
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added solution.java and explanation.md, please check.