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Solution #2413 - Mridul/Edited - 16/03/2025 #35
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Problems/#2413 - Smallest Even Multiple - Easy/Explanation.md
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# Explanation of the `smallestEvenMultiple` Code | ||
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This Java class provides a solution to calculate the smallest even multiple of a given number `n`. | ||
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--- | ||
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## Class: `Solution` | ||
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### Method: `smallestEvenMultiple(int n)` | ||
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#### **Purpose** | ||
The method returns the smallest even multiple of the integer `n`. | ||
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#### **Parameters** | ||
- `n`: A positive integer. | ||
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#### **Logic** | ||
1. **Check if `n` is Even**: | ||
- If `n % 2 == 0` (i.e., `n` is divisible by 2 without a remainder), then `n` is already an even number. In this case, return `n`. | ||
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2. **Calculate the Smallest Even Multiple**: | ||
- If `n` is odd, its smallest even multiple is `n * 2`, because multiplying any odd number by 2 produces the smallest even multiple of that number. | ||
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3. **Return the Result**: | ||
- Depending on the condition, either `n` or `n * 2` is returned. | ||
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--- | ||
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### Example Execution | ||
#### Input: | ||
```java | ||
int n = 5; | ||
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Time Complexity: O(1) | ||
Space Complexity: O(1) | ||
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class Solution { | ||
public int smallestEvenMultiple(int n) { | ||
if(n%2==0) return n; | ||
else return n*2; | ||
} | ||
} |
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looks good! Explain the complexity and it should be good to go!