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Sum of ap #3125

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cc0fca2
Sum Of Ap by using formula for O(1) time complexity
xandersavvy Mar 30, 2022
631f4c0
Sum Of AP using formula for O(1) complexity
xandersavvy Mar 30, 2022
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15 changes: 8 additions & 7 deletions Arithmetic_Progression/Arithmetic_Progression.c
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Original file line number Diff line number Diff line change
Expand Up @@ -13,13 +13,14 @@
// To find sum of the arithmetic progression
int SumOfAP(int a, int d, int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
{
sum = sum + a;
a = a + d;
}
return sum;
// int sum = 0;
// for (int i = 0; i < n; i++)
// {
// sum = sum + a;
// a = a + d;
// }
// return sum;
return (n/2)*(2*a+((n-1)*d));
}

int main() {
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15 changes: 8 additions & 7 deletions Arithmetic_Progression/Arithmetic_Progression.cpp
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Original file line number Diff line number Diff line change
Expand Up @@ -14,13 +14,14 @@ using namespace std;
// To find sum of the arithmetic progression
int SumOfAP (int a, int d, int n)
{
int sum = 0;
for (int i = 0; i < n; i++)
{
sum = sum + a;
a = a + d;
}
return sum;
// int sum = 0;
// for (int i = 0; i < n; i++)
// {
// sum = sum + a;
// a = a + d;
// }
// return sum;
return (n/2)*(2*a+((n-1)*d));
}

int main() {
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13 changes: 7 additions & 6 deletions Arithmetic_Progression/Arithmetic_Progression.go
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Original file line number Diff line number Diff line change
Expand Up @@ -14,12 +14,13 @@ import (
)

func SumOfAP(a int, d int, n int) int {
var sum = 0
for i := 0; i < n; i++ {
sum = sum + a
a = a + d
}
return sum
// var sum = 0
// for i := 0; i < n; i++ {
// sum = sum + a
// a = a + d
// }
// return sum
return (n/2)*(2*a+((n-1)*d));
}

func main() {
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15 changes: 8 additions & 7 deletions Arithmetic_Progression/Arithmetic_Progression.java
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Expand Up @@ -12,13 +12,14 @@ The nth term of an A.P. is defined as (a + (n - 1)*d)

class Arithmetic_Progression {
static int SumOfAP(int a, int d, int n) {
int sum = 0;
for (int i = 0; i < n; i++)
{
sum = sum + a;
a = a + d;
}
return sum;
// int sum = 0;
// for (int i = 0; i < n; i++)
// {
// sum = sum + a;
// a = a + d;
// }
// return sum;
return (n/2)*(2*a+((n-1)*d));
}

public static void main(String args[]) {
Expand Down