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Old behavior when there is no previous_satisfier #257

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Old behavior when there is no previous_satisfier #257

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621c41b
the smallest change to bring back pre-79 behavior
Eh2406 Nov 19, 2024
4ce8684
only allocate the start term if it's needed
Eh2406 Nov 19, 2024
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18 changes: 12 additions & 6 deletions src/internal/partial_solution.rs
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Original file line number Diff line number Diff line change
Expand Up @@ -487,10 +487,14 @@ impl<DP: DependencyProvider> PartialSolution<DP> {

satisfied_map.insert(
satisfier_package,
satisfier_pa.satisfier(
satisfier_package,
&accum_term.intersection(&incompat_term.negate()),
),
if accum_term.subset_of(incompat_term) {
(None, 0, DecisionLevel(1))
} else {
satisfier_pa.satisfier(
satisfier_package,
&accum_term.intersection(&incompat_term.negate()),
)
},
);

// Finally, let's identify the decision level of that previous satisfier.
Expand All @@ -512,14 +516,16 @@ impl<P: Package, VS: VersionSet, M: Eq + Clone + Debug + Display> PackageAssignm
package: &P,
start_term: &Term<VS>,
) -> (Option<IncompId<P, VS, M>>, u32, DecisionLevel) {
let empty = Term::empty();
// Indicate if we found a satisfier in the list of derivations, otherwise it will be the decision.
let idx = self
.dated_derivations
.as_slice()
.partition_point(|dd| !dd.accumulated_intersection.is_disjoint(start_term));
if let Some(dd) = self.dated_derivations.get(idx) {
debug_assert_eq!(dd.accumulated_intersection.intersection(start_term), empty);
debug_assert_eq!(
dd.accumulated_intersection.intersection(start_term),
Term::empty()
);
return (Some(dd.cause), dd.global_index, dd.decision_level);
}
// If it wasn't found in the derivations,
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4 changes: 2 additions & 2 deletions tests/examples.rs
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Original file line number Diff line number Diff line change
Expand Up @@ -237,8 +237,8 @@ fn confusing_with_lots_of_holes() {
};
assert_eq!(
&DefaultStringReporter::report(&derivation_tree),
r#"Because there is no available version for bar and foo 1 | 2 | 3 | 4 | 5 depends on bar, foo 1 | 2 | 3 | 4 | 5 is forbidden.
And because there is no version of foo in <1 | >1, <2 | >2, <3 | >3, <4 | >4, <5 | >5 and root 1 depends on foo, root 1 is forbidden."#
r#"Because foo 1 | 2 | 3 | 4 | 5 depends on bar and there is no version of foo in <1 | >1, <2 | >2, <3 | >3, <4 | >4, <5 | >5, foo depends on bar.
And because there is no available version for bar and root 1 depends on foo, root 1 is forbidden."#
);
derivation_tree.collapse_no_versions();
assert_eq!(
Expand Down