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Prasanth Assignment submit #11

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Prasanth Assignment submit #11

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22 changes: 22 additions & 0 deletions assignment.html
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<!DOCTYPE html><html>
<head>
<title>Sample HTML page</title>
<script src="main.js"></script>
</head>
<body>
<div>
<!--<p>Calculating factorial number</p>
<input type="text" id="factorial"/>
<button type="button" onclick="onFactorialBtnClick();">Factorial</button>
<p>Find the sum of the first 500 natural numbers</p> -->
<input type="text" id="naturalNumber"/>
<button type="button" onclick="sumofNaturalNum();">submit</button>
<p>please check output in console</p>

</div>

<div id="output">

</div>
</body>
</html>
88 changes: 88 additions & 0 deletions main.js
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function factorial(number) {
if (number === 0) {
return 1;
}
return number * factorial(number - 1);
}

function sumofNaturalNum(){
/* sn = n(n+1)/2*/
//getting factorial number

console.log('Factorial for the given number is '+factorial(document.getElementById("naturalNumber").value));

//calculating sum of natural number
var input = document.getElementById("naturalNumber").value;
var sum = Number(input)*(Number(input)+1)/2;
console.log('Sum of the given natural number is '+sum);
getMultipleSum();
powerofTwo();
fizzBuzz();
palindrome();

}

function getMultipleSum(){
var input = document.getElementById("naturalNumber").value;
var sum = 0;
for(var i =0;i<Number(input);i++) {
if(i%3==0 || i%5==0){
sum = sum+i;
}
}
console.log('sum of all the multiples of 3 or 5 for the number is '+sum);
}

function powerofTwo(){
var res = 0;
var input = document.getElementById("naturalNumber").value;
for (var i=Number(input); i>=1; i--)
{

if ((i & (i-1)) == 0)
{
res = i;
break;
}
}
console.log('closest power of 2 which is less than or equal to the number is '+res );
}

function fizzBuzz(){
var inputVal = document.getElementById("naturalNumber").value;
var str="";
for (var i=1;i<=Number(inputVal);i++)
{
if(i%3==0)
{
str+=",fizz"
}
if (i%5==0)
{
str+=",buzz"
}
if (!(i%3==0||i%5==0))
{
str+=','+i;
}

}
console.log(str);
}

function palindrome(){
var inputVal = "sister";//document.getElementById("naturalNumber").value;
var stringArr = String(inputVal).split("");
stringArr.reverse();
var reverseStr="";
for(var i = 0;i<stringArr.length;i++){
reverseStr = reverseStr+stringArr[i];
}
if(reverseStr.toUpperCase() === inputVal.toUpperCase()){
console.log('Given string is palindrome '+ reverseStr);
}else{
console.log('Given string not a palindrome '+ reverseStr);
}
}