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Cuts the run time to half #167
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its useful if we make the loop go only to integer less than a/2 as ((a)/(a/2))==2 and ((a)/(a))==1 so ((a)/(x)) for x a/2<x<a will have (a%x)!=0 always by simple analysis
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its useful if we make the loop go only to integer less than a/2 as ((a)/(a/2))==2 and ((a)/(a))==1 so ((a)/(x)) for x a/2<x<a will have (a%x)!=0
always by simple analysis