lab done

index.js

@@ -1,7 +1,45 @@
 // Iteration 1: Names and Input
 
+const hacker1 = "Andrew";
+console.log(`The driver's name is ${hacker1}`)
+
+const hacker2 = "Claudia";
+console.log(`The navigator's name is ${hacker2}`)
 
 // Iteration 2: Conditionals
 
+if (hacker1.length > hacker2.length) {
+  console.log (`The driver has the longest name, it has ${hacker1.length} characters.`)
+} else if (hacker1.length < hacker2.length) {
+  console.log (`It seems that the navigator has the longest name, it has ${hacker2.length} characters.`)
+} else {
+  console.log (`Wow, you both have equally long names, ${hacker1.length} characters!`)
+}
 
 // Iteration 3: Loops
+
+// 3.1 Print the characters of the driver's name, separated by space, and in capital letters
+
+let hacker1CapLet = ""
+for (let i=0; i<hacker1.length; i++) {
+  hacker1CapLet += hacker1[i].toUpperCase() + " ";
+}
+console.log(hacker1CapLet);
+
+// 3.2 Print all the characters of the navigator's name in reverse order
+
+let hacker1Reverse = ""
+for (let i=hacker1.length-1; i>=0; i--) {
+  hacker1Reverse += hacker1[i]
+}
+console.log(hacker1Reverse)
+
+// 3.3 Lexicographic order
+
+if (hacker1.localeCompare(hacker2) < 0) {
+  console.log(`${hacker1} The driver's name goes first.`);
+} else if (hacker1.localeCompare(hacker2) > 0) {
+  console.log(`${hacker2} Yo, the navigator goes first, definitely.`);
+} else {
+  console.log("What?! You both have the same name?");
+}