Update timeout example in README.rst #134
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Corrects the error being thrown in the timeout example and makes it more meaningful by adding sleep to simulate tasks and printing results from processes that finish.
noxdafox
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Jun 26, 2024
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| def function(foo, bar=0): | ||
| time.sleep(foo) # simulate a task | ||
| return foo |
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bar is not used anymore, the original README was returning foo + bar.
noxdafox
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Jun 26, 2024
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| with ProcessPool(max_workers=5, max_tasks=10) as pool: | ||
| for index in range(0, 10): | ||
| future = pool.schedule(function, [index], {'bar':1}, timeout=TIMEOUT_SECONDS) |
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Please use KW arguments properly to better indicate how to call this function.
future = pool.schedule(function, args=[index], kwargs={'bar':1}, timeout=TIMEOUT_SECONDS)
noxdafox
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Jun 26, 2024
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noxdafox
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noxdafox
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Thanks for the contribution!
I did not understand what was the issue with the TimeoutError handling.
Could you please make the fixes as requested in the comments?
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Corrects the error being thrown in the timeout example in README and makes it more meaningful by adding sleep to simulate tasks and printing results from processes that finish.