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apply_member_constraints
: fix placeholder check
#142071
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29 changes: 29 additions & 0 deletions
29
tests/ui/nll/member-constraints/non-root-universe-existential-1.rs
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,29 @@ | ||
//@ check-pass | ||
//@ revisions: current next | ||
//@ ignore-compare-mode-next-solver (explicit revisions) | ||
//@[next] compile-flags: -Znext-solver | ||
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trait Proj<'a> { | ||
type Assoc; | ||
} | ||
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impl<'a, 'b, F: FnOnce() -> &'b ()> Proj<'a> for F { | ||
type Assoc = (); | ||
} | ||
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fn is_proj<F: for<'a> Proj<'a>>(f: F) {} | ||
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fn define<'a>() -> impl Sized + use<'a> { | ||
// This defines the RPIT to `&'unconstrained_b ()`, an inference | ||
// variable which is in a higher universe as gets created inside | ||
// of the binder of `F: for<'a> Proj<'a>`. This previously caused | ||
// us to not apply member constraints. | ||
// | ||
// This was unnecessary. It is totally acceptable for member regions | ||
// to be able to name placeholders from higher universes, as long as | ||
// they don't actually do so. | ||
is_proj(define::<'a>); | ||
&() | ||
} | ||
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fn main() {} |
31 changes: 31 additions & 0 deletions
31
tests/ui/nll/member-constraints/non-root-universe-existential-2.rs
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Original file line number | Diff line number | Diff line change | ||||
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@@ -0,0 +1,31 @@ | ||||||
//@ check-pass | ||||||
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// Unlike `non-root-universe-existential-1.rs` this previously | ||||||
// compiled as it simnply didn't define the hidden type of | ||||||
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Suggested change
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// `impl Iterator` when projecting through it. We will do so | ||||||
// with the new solver. Further minimizing this is challenging. | ||||||
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struct Type(Vec<Type>); | ||||||
enum TypeTreeValueIter<'a, T> { | ||||||
Once(T), | ||||||
Ref(&'a ()), | ||||||
} | ||||||
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impl<'a, T> Iterator for TypeTreeValueIter<'a, T> { | ||||||
type Item = T; | ||||||
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fn next(&mut self) -> Option<Self::Item> { | ||||||
loop {} | ||||||
} | ||||||
} | ||||||
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fn item<I: Iterator<Item: Iterator>>(x: I) -> <I::Item as Iterator>::Item { | ||||||
loop {} | ||||||
} | ||||||
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fn get_type_tree_values<'a>(ty: &'a Type) -> impl Iterator<Item = &'a Type> { | ||||||
let _: &'a Type = item(std::iter::once(ty).map(get_type_tree_values)); | ||||||
TypeTreeValueIter::<'a, &'a Type>::Once(ty) | ||||||
} | ||||||
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fn main() {} |
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This comment is weird: "It is totally acceptable ... as long as they don't actually do so"?
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"to be able to" vs "to do"
As in: it's fine for the member region to be an existential region created in a higher universe, as long as it doesn't actually name any placeholder from that higher universe.
How would you restructure this comment? Is the following clearer?
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This is the most clear